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but if the interfaces have different notions of what f means and does, you need to explicitly implement the functions inherited from each interface separately. The language provides support for doing this, as in Listing 9-9. Listing 9-9. Implementing Inherited Functions Separately // explicit_interface_implementation.cpp using namespace System; interface class I1 { void f(); }; interface class I2 { void f(); }; ref class R : I1, I2 { public: virtual void f1() = I1::f { Console::WriteLine("R::f1 == I1::f"); } virtual void f2() = I2::f { Console::WriteLine("R::f2 == I2::f"); } }; int main() { R^ r = gcnew R(); I1^ i1 = r; I2^ i2 = r; r->f1(); r->f2(); // r->f(); i1->f(); i2->f(); // r->I1::f(); // r->I1::f1(); } The final two calls are not supported. The output of Listing 9-9 is as follows: // OK -- call through the object. // OK -- call through the object. // Error: f is not a member of R. // OK -- call f1. // OK -- call f2. // Compiler error: "direct call will fail at runtime". // Error: f1 is not a member of I1. .net code 128 reader C# Code 128 Reader SDK to read, scan Code 128 in C#.NET class ...
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